Draw equilateral triangles
BCA1,
ACB1
and
ABC1
on the inside of the given triangle ABC.
Then
A1B1C1
is the Inner Fermat Triangle.
The Second Fermat Point F is the perspector of triangle ABC and
the Inner Fermat Triangle. That is,
F is the point of concurrence of the lines
AA1, BB1 and CC1.
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