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Second Power Point |
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Given ∆ABC with sidelengths a = BC, b = CA and c = AB. Let point Pa divides the segment BC in ratio BPa : PaC = c3 : b3. Let point Pb divides the segment CA in ratio CPb : PbA = a3 : c3, and let point Pc divides the segment AB in ratio APc : PcB = b3 : a3. Then the lines APa, BPb and CPc concur in a point known as the Second Power Point. 
Point P = Second Power Point. |
