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Third Power Point |
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Given ∆ABC with sidelengths a = BC, b = CA and c = AB. Let point Pa divides the segment BC in ratio BPa : PaC = c4 : b4. Let point Pb divides the segment CA in ratio CPb : PbA = a4 : c4, and let point Pc divides the segment AB in ratio APc : PcB = b4 : a4. Then the lines APa, BPb and CPc concur in a point known as the Third Power Point. 
Point P = Third Power Point. |
